If b2 -4ac- 0 then the roots of quadratic equation ax2 - bx - c -0 is-

The correct option is C b/2a±√(b^2 4ac)/2a If b^2 4ac≥ 0 Then the roots are real.HenceBy using quadratic formula, we get the roots as b±√(b^2 4 ...

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Standard X

Mathematics

Quadratic Formula

If b2 -4ac≥...

Question

If $b^{2} - 4 a c \geq 0$ then the roots of quadratic equation $a x^{2} + b x + c = 0$ is-

\frac{b}{2 a} \pm \frac{\sqrt{b^{2} - 4 a c}}{2 a}

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- \frac{b}{2 a} \pm \frac{\sqrt{b^{2} + 4 a c}}{2 a}

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\frac{b}{2 a} \pm \frac{\sqrt{b^{2} + 4 a c}}{2 a}

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- \frac{b}{2 a} \pm \frac{\sqrt{b^{2} - 4 a c}}{2 a}

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Solution

The correct option is C $- \frac{b}{2 a} \pm \frac{\sqrt{b^{2} - 4 a c}}{2 a}$
If $b^{2} - 4 a c \geq 0$
Then the roots are real.
Hence
By using quadratic formula, we get the roots as
$\frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$
Hence, option 'D' is correct.

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Similar questions

If b² – 4ac = 0 then The roots of the Quadratic equation ax² + bx + c = 0 are given by :

The roots of a quadratic equation $a x^{2} + b x + c = 0$ are given by $\frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ , provided $b^{2} - 4 a c \geq 0$ .

Q. Prove that root of equation

a x^{2} + b x + c = 0

\frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}

Q. Which of the given formulae is the correct one to find out the roots of the quadratic equation

a x^{2} + b x + c = 0

Q. Prove the root of equation

{a x}^{2} + b x + c = 0

\Rightarrow x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}

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If b2−4ac≥0 then the roots of quadratic equation ax2+bx+c=0 is-

The correct option is C −b2a±√b2−4ac2aIf b2−4ac≥0Then the roots are real.HenceBy using quadratic formula, we get the roots as−b±√b2−4ac2aHence, option 'D' is correct.

If $b^{2} - 4 a c \geq 0$ then the roots of quadratic equation $a x^{2} + b x + c = 0$ is-

The correct option is C $- \frac{b}{2 a} \pm \frac{\sqrt{b^{2} - 4 a c}}{2 a}$
If $b^{2} - 4 a c \geq 0$
Then the roots are real.
Hence
By using quadratic formula, we get the roots as
$\frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$
Hence, option 'D' is correct.