CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Combination

If B=A, |...

Question

If $B = A$ , $| P | = | Q | = 1$ , then $a d j (Q^{- 1} {B P}^{- 1)}$ is

A

P . Q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

Q . a d j (A) . P

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

P . a d j (A) . Q

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

P . A^{- 1} . Q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $P . a d j (A) . Q$
Given, $B = A, | P | = | Q | = 1$
Consider, $a d j (Q^{- 1} {B P}^{- 1)}$
$= (a d j P^{- 1}) (a d j B) (a d j Q^{- 1}) (∵ a d j (A B C) = (a d j C) (a d j B) (a d j A)$
$= \frac{P}{| P |} (a d j B) \frac{Q}{| Q |} (∵ a d j P^{- 1} = \frac{P}{| P |})$
$= P (a d j A) Q$ ( $∵ A = B$ )

Suggest Corrections

thumbs-up

0

Similar questions

B = A

| P | = | Q | = 1

a d j ((Q^{- 1} {B P}^{- 1})

adj B = A, | P | = | Q | = 1,

adj (Q^{- 1} B P^{- 1})

a d j B = A, | P | = | Q | = 1

a d j (Q^{- 1} B P^{- 1})

P = [a_{i j}]_{n \times n}

be any matrix and it is non singular matrix. If |P| = |Q| = 1 and adj B = A, then

a d j (Q^{- 1} B P^{- 1})

Let A = {p. q, r, s} and B = {1, 2, 3}. Which of the following relations from A to B is not a function?
(i) $R_{1} = {(p, 1), (q, 2), (r, 1), (s, 2)}$
(ii) $R_{2} = {(p, 1), (q, 1), (r, 1), (s, 1)}$
(iii) $R_{3} = {(p, 1), (q, 2), (r, 1), (s, 2)}$
(iv) $R_{4} = {(p, 2), (q, 3), (r, 2), (s, 2)}$

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Combinations

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon