If b is the mean proportion between 3 and 9- b value is-A- -3B- 3 -3- 3-3D- 3

The correct option is B 3 √(3) If b is the mean proportion , then we have b^2 = a × c ∴ b = √(ac) , where a and c are given values a= 3 b= 9 b = √(3 × 9) ...

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Standard VII

Mathematics

Proportions

If b is the m...

Question

If b is the mean proportion between 3 and 9 , b value is :

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$\sqrt{3}$

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$3 \sqrt{3}$

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$3 + \sqrt{3}$

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Solution

The correct option is C
$3 \sqrt{3}$

If b is the mean proportion , then we have

$b^{2}$ = $a \times c$

$∴ b = \sqrt{a c}$ , where a and c are given values

a= 3

b= 9

$b = \sqrt{3 \times 9} = \sqrt{3} \times \sqrt{9} = \sqrt{3} \times 3$

$b = 3 \sqrt{3}$

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If b is the mean proportion between 3 and 9 , b value is :

The correct option is C 3√3 If b is the mean proportion , then we have b2 = a×c ∴ b=√ac , where a and c are given values a= 3 b= 9 b=√3×9=√3×√9=√3×3 b=3√3

The correct option is C
$3 \sqrt{3}$

If b is the mean proportion , then we have

$b^{2}$ = $a \times c$

$∴ b = \sqrt{a c}$ , where a and c are given values

a= 3

b= 9

$b = \sqrt{3 \times 9} = \sqrt{3} \times \sqrt{9} = \sqrt{3} \times 3$

$b = 3 \sqrt{3}$