Question

If $\overline{a}=b,c\in R$ and $|b{|}^2<c$, then the equation $z\overline{z}+az+b\overline{z}+c=0$

• A. Has no solution
• B. Exactly two solutions
• C. Infinite number of solutions
• D. None of these

Answer 1

The correct option is A Has no solution

$z\overline{z}+b\overline{z}+\overline{b}z+c=0$ represents the equation of a circle where $b\overline{b}\ge c$.
However, it is mentioned that $b\overline{b}<c$.
Hence, the circle is not possible.
Hence, (a) is correct.