If ¯a=b,c∈R and |b|2>c, then z¯z+az+b¯z+c=0 represents
A
A circle
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
A parabola
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
A straight line
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Finite number of points
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B A circle z¯z+az+b¯z+c=0 Or |z|2+az+¯a¯z+c=0 Or az+¯az+c+|z|2=0 If z=x+iy we get and a=ax+iay x2+y2+(ax+iay)(x+iy)+(ax−iay)(x−iy)+c=0 x2+y2+xax−yax+i(xay+yax)+xax−yax−i(xay+yax)+c=0 Or x2+y2+2xax−2yax+c=0 This represents an equation of a circle.