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Question

If ¯a,¯b,¯c are three non-coplanar non-zero vectors and ¯r is any vector in space, then (¯aׯb)×(¯rׯc)+(¯bׯc)×(¯rׯa)+(¯cׯa)×(¯rׯb) is equal to

A
2[¯a ¯b ¯c]¯r
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B
3[¯a ¯b ¯c]¯r
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C
[¯a ¯b ¯c]¯r
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D
4[¯a ¯b ¯c]¯r
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Solution

The correct option is A 2[¯a ¯b ¯c]¯r
(a×b)×(r×c)
=((a×b).c)r(a×b).r)c
=[abc]r[abr]c
Simillarly,
(b×c)×(r×a)
=[bca]r[bcr]a
and
(c×a)×(r×b)
=[cab]r[car]b
When we add all three, we get,
2[abc]r

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