If BD is the angular bisector of - ABD- then find the - DBC-A- 130-B- 125-C- 75-D- 65-

The correct option is D 65^∘The line segment that divides the nbsp;angle nbsp;into two equal parts is called an angular bisector. So, ∠ ABD = ∠ DBC = 65^∘ ...

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Byju's Answer

Standard VI

Mathematics

Angle Bisector and Its Construction

If BD is the ...

Question

If BD is the angular bisector of ∠ABD , then find the ∠DBC.

130^{\circ}

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125^{\circ}

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65^{\circ}

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75^{\circ}

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Solution

The correct option is C $65^{\circ}$
The line segment that divides the angle into two equal parts is called an angular bisector.
So,
$∠ A B D = ∠ D B C = 65^{\circ}$

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Similar questions

Q. If BD is the angular bisector of ∠ABD , then find the ∠DBC.

Side $B C$ of $Δ A B C$ has been produced to $D$ on left and to $E$ on right hand side of BC such that $∠ A B D = 125^{\circ}$ and $∠ A C E = 130^{\circ}$ . Then $∠ A =$ ?
(a) $50^{\circ}$
(b) $55^{\circ}$
(c) $65^{\circ}$
(d) $75^{\circ}$

Q. Side BC of ∆ABC has been produced to D on left hand side and to E on right hand side such that ∠ABD = 125° and ∠ACE = 130°. Then ∠A = ?
(a) 65°
(b) 75°
(c) 50°
(d) 55°

The diagonals AC and BD of a parallelogram ABCD intersect each other at the point O . If ∠ D A C = 35^{\circ} and ∠ A O B = 80^{\circ}, then find the value of ∠ D B C .

Q. If the vertical angle of a triangle is 130°, then the angle between the bisectors of the base angles of the triangle is
(a) 65°
(b) 100°
(c) 130°
(d) 155°

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If BD is the angular bisector of ∠ABD , then find the ∠DBC.

The correct option is C 65∘The line segment that divides the angle into two equal parts is called an angular bisector. So, ∠ABD=∠DBC=65∘

The correct option is C $65^{\circ}$
The line segment that divides the angle into two equal parts is called an angular bisector.
So,
$∠ A B D = ∠ D B C = 65^{\circ}$