Question

If BE || AC and CF || AB meet PQ at E and F, respectively. The base and altitude of ΔABC are 6 cm and 8 cm, respectively. Then, find the area of ΔACF.

Answer 1

CF when drawn parallel to AB, forms parallelogram ABCF.

AC is the diagonal of the parallelogram that divides ABCF into 2 equal triangles ABC and ACF.

So, Area of ΔACF = Area of ΔABC = $\frac{1}{2}\times 6\times 8=24c{m}^2$