Let A=⎡⎢⎣12a014001⎤⎥⎦
⇒A2=⎡⎢⎣12a014001⎤⎥⎦⎡⎢⎣12a014001⎤⎥⎦=⎡⎢⎣142a+8018001⎤⎥⎦
A3=⎡⎢⎣163a+240112001⎤⎥⎦
A4=⎡⎢⎣184a+480116001⎤⎥⎦
⋅ ⋅
⋅ ⋅
⋅ ⋅
An=⎡⎢
⎢
⎢
⎢⎣12nna+8n−1∑k=0k014n001⎤⎥
⎥
⎥
⎥⎦
Now,⎡⎢⎣12a014001⎤⎥⎦n=⎡⎢⎣11820070136001⎤⎥⎦⇒⎡⎢
⎢
⎢
⎢⎣12nna+8n−1∑k=0k014n001⎤⎥
⎥
⎥
⎥⎦=⎡⎢⎣11820070136001⎤⎥⎦
⇒2n=18⇒n=9⇒na+8n−1∑k=0k=2007⇒9a+88∑k=0k=2007⇒9a+8×36=2007⇒9a=1719⇒a=191
∴[9+191100]=[2]=2