The correct option is A [ 1 amp; 1; 1 amp; 0 ][ 2 amp; 1; 3 amp; 2 ]A[ 3 amp; 2; 5 amp; 3 ]=[ 1 amp; 0; 0 amp; 1 ] ...

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Additive Identity and Additive Inverse of a Matrix

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Question

If $[\begin{matrix} 2 & 1 3 & 2 \end{matrix}] A [\begin{matrix} - 3 & 2 5 & - 3 \end{matrix}] = [\begin{matrix} 1 & 0 0 & 1 \end{matrix}]$ , then A =

[\begin{matrix} 1 & 1 1 & 0 \end{matrix}]

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[\begin{matrix} 1 & 1 0 & 1 \end{matrix}]

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[\begin{matrix} 1 & 0 1 & 1 \end{matrix}]

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- [\begin{matrix} 1 & 1 1 & 0 \end{matrix}]

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Solution

The correct option is A $[\begin{matrix} 1 & 1 1 & 0 \end{matrix}]$
$[\begin{matrix} 2 & 1 3 & 2 \end{matrix}] A [\begin{matrix} - 3 & 2 5 & - 3 \end{matrix}] = [\begin{matrix} 1 & 0 0 & 1 \end{matrix}] A = [\begin{matrix} 2 & - 1 - 3 & 2 \end{matrix}] [\begin{matrix} 1 & 0 0 & 1 \end{matrix}] [\begin{matrix} - 3 & - 2 - 5 & - 3 \end{matrix}] (- 1) = [\begin{matrix} 2 & - 1 - 3 & 2 \end{matrix}] [\begin{matrix} 3 & 2 5 & 3 \end{matrix}] = [\begin{matrix} 1 & 1 1 & 0 \end{matrix}]$

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Similar questions

[\begin{matrix} 2 & 1 3 & 2 \end{matrix}] A [\begin{matrix} - 3 & 2 5 & - 3 \end{matrix}] = [\begin{matrix} 1 & 0 0 & 1 \end{matrix}]

Compute the indicated products.
$(i) [\begin{matrix} a & b - b & a \end{matrix}] [\begin{matrix} a & - b b & a \end{matrix}]$

$(i i) ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦ [234]$

$(i i i) [\begin{matrix} 1 & - 2 2 & 3 \end{matrix}] [\begin{matrix} 1 & 2 & 3 2 & 3 & 1 \end{matrix}]$

$(i v) ⎡ ⎢ ⎣ \begin{matrix} 2 & 3 & 4 3 & 4 & 5 4 & 5 & 6 \end{matrix} ⎤ ⎥ ⎦ ⎡ ⎢ ⎣ \begin{matrix} 1 & - 3 & 5 0 & 2 & 4 3 & 0 & 5 \end{matrix} ⎤ ⎥ ⎦$

$(v) ⎡ ⎢ ⎣ \begin{matrix} 2 & 1 3 & 2 - 1 & 1 \end{matrix} ⎤ ⎥ ⎦ [\begin{matrix} 1 & 0 & 1 - 1 & 2 & 1 \end{matrix}]$

$(v i) [\begin{matrix} 3 & - 1 & 3 - 1 & 0 & 2 \end{matrix}] ⎡ ⎢ ⎣ \begin{matrix} 2 & - 3 1 & 0 3 & 1 \end{matrix} ⎤ ⎥ ⎦$

Identify the matrix $⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 12345 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦$

[\begin{matrix} 1 & {sin}^{2} x {cot}^{2} x & - {sec}^{2} x \end{matrix}] + [\begin{matrix} {tan}^{2} x & {cos}^{2} x 1 & 1 \end{matrix}]

Compute the indicated product.
$[\begin{matrix} 3 & - 1 & 3 - 1 & 0 & 2 \end{matrix}]$ $⎡ ⎢ ⎣ \begin{matrix} 2 & - 3 1 & 0 3 & 1 \end{matrix} ⎤ ⎥ ⎦$

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