If [2xxy3y][32]=[169], then y = ___.
[2xxy3y][32]=[169]
[6x+2x3y+6y]=[169]
[8x9y]=[169]
Comparing the two matrices, we get
8x = 16
→x = 2
9y = 9
→y = 1
Find y, if [2xxy3y][32]=[169] ___.
Find x and y, if [2xxy3y][32]=[169]
Find the value of x and y, if [x+yy2xx−y][2−1]=[32]
Evaluate (8a3−27b3)(64x3+y3), where (64x3+y3)≠0.