If ⎡⎢⎣413⎤⎥⎦A=⎡⎢⎣−484−121−363⎤⎥⎦, find A. If A=[a,b,c], find the value of a+b+c.
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Solution
Given, ⎡⎢⎣413⎤⎥⎦A=⎡⎢⎣−484−121−363⎤⎥⎦ ⇒⎡⎢⎣413⎤⎥⎦[abc]=⎡⎢⎣−484−121−363⎤⎥⎦ ⇒⎡⎢⎣4a4b4cabc3a3b3c⎤⎥⎦=⎡⎢⎣−484−121−363⎤⎥⎦ Comparing elements, we get a=−1,b=2,c=1