Question

If $\left[\begin{array}{cc}4& -3\\ 2& 16\end{array}\right]$ = $\left[\begin{array}{cc}4& -3\\ 2& 2^t\end{array}\right]$, then t = _______

• A. $2$
• B. $3$
• C. $4$
• D. $5$

Answer 1

The correct option is C $4$

By comparing the corresponding elements, we have

$2^t$ = $16$
$\Rightarrow 2^t=2\times 2\times \times 2=2^4$

$\therefore t=4$.