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Question

If [x+32y+xz1w8]=[x1032w] then find the value of |x+y|+|z+w|

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Solution

As the given matrices are equal so their corresponding elements are equal.

x+3=x1

2x=13=4..............(1)

x=42=2

2y+x=02y2=0 from (1)

2y=2

y=22=1

y=1.............(2)

z1=3z=3+1=4

z=4.........(3)

4w8=2w

4w2w=8

2w=8 (or) w=82=4

w=4...........(4)

Hence |x+y|+|z+w|

=|2+1|+|4+4|

|1|+|8|

=1+8=9

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