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Question

If x+3z+42y76a10b3210=063y2632c+22b+4210, then the value of a is:

A
1
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B
2
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C
1
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D
2
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Solution

The correct option is B 2
As the given matrices are equal , therefore, their corresponding elements must be equal. Comparing the element a22 of both matrices, we get
a1=3,
a=2

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