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Question

If [x+y2x+zxy2z+w]=[47010], then find y+z+w

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Solution

We have [x+y2x+zxy2z+w]=[47010]
Comparing the elements we have
x+y=4,2x+z=7,xy=0 and 2z+w=10
Solving these equations we get x=2 and y=2,z=3,w=4
then y+z+w=9

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