If [x−yz2x−yw]=[−1405], find the value of x+y
If [x−yz2x−y1]=[−1405]
By equality of matrices, we have: x−y=−1,2x−y=0
On solving these eqs., we get : x=1,y=2. So, x+y=3.
Let A=[2432],B=[13−25]
Find the value of the following: BA
Given [xy+23z−1]=[3132] ; find x, y and z.
If x[23]+y[−11]=[105], then find the values of x and y.
If 3[xyzw]=[x6−12w]+[4x+yx+w3], find the values of x, y, z and w.
Find X and Y if (i)X+Y=[7025] and X−Y=[30−15]
(ii)2X+3Y=[2340]and3X+2Y=[2−2−15]