Question

If
$\begin{array}{c}Pstandsfor{}^{\prime }{+}^{\prime }\\ Qstandsfor{}^{\prime }{-}^{\prime }\\ Rstandsfor{}^{\prime }{\times }^{\prime }\\ Sstandsfor{}^{\prime }{÷}^{\prime }\end{array}$,
then $2P4Q6R8S1R3Q5P7$ is

• A. $0$
• B. $-136$
• C. $-150$
• D. $2$

Answer 1

The correct option is B $-136$

$2P4Q6R8S1R3Q5P7$
$\to 2+4-6\times 8÷1\times 3-5+7$
$\to BODMASRULES\Rightarrow 2+4-(6\times 8\times 3)-5+7$
$=6-144+2=-136$