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Question
If T5=81T2=3 find T3 and T4
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Solution
Given T5=a+4d=81 T2=a+d=3⇒T5−T2=a+4d−a−d=81−3⇒3d=27∴d=273=9⇒a+d=3⇒a=3−d=3−9=−6Now, T3=a+2d=−6+2×9=−6+18=12and T4=a+3d=−6+3×9=−6+27=21∴T1=a=−6,T3=12 and T4=21
T2=a+d=3
⇒T5−T2=a+4d−a−d=81−3
⇒3d=27∴d=273=9
⇒a+d=3⇒a=3−d=3−9=−6
Now, T3=a+2d=−6+2×9=−6+18=12
and T4=a+3d=−6+3×9=−6+27=21
∴T1=a=−6,T3=12 and T4=21
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