Question

If $\left(\begin{array}{c}\frac{-11}{14}\times \frac{6}{13}\end{array}\right)+\left(\begin{array}{c}\frac{-11}{14}\times \frac{7}{13}\end{array}\right)=\frac{m}{14}$.Then find $-m$

Answer 1

$\left(\begin{array}{c}\frac{-11}{14}\times \frac{6}{13}\end{array}\right)+\left(\begin{array}{c}\frac{-11}{14}\times \frac{7}{13}\end{array}\right)$
Using distributive property of multiplication,
$=\frac{-11}{14}(\frac{6}{13}+\frac{7}{13})$

$=\frac{-11}{14}\left(\frac{6+7}{13}\right)$

$=\frac{-11}{14}\left(\frac{13}{13}\right)$

$=\frac{-11}{14}$

$m=-11$