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Byju's Answer
Standard XII
Mathematics
Inverse of a Matrix
If 1+a 1 ...
Question
If
∣
∣ ∣
∣
1
+
a
1
1
1
1
+
b
1
1
1
1
+
c
∣
∣ ∣
∣
=
0
then
a
−
1
+
b
−
1
+
c
−
1
equals
A
1
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B
a
b
c
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C
−
1
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D
None of these
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Solution
The correct option is
D
−
1
∣
∣ ∣
∣
1
+
a
1
1
1
1
+
b
1
1
1
1
+
c
∣
∣ ∣
∣
=
0
=
(
1
+
a
)
(
1
+
b
+
c
+
b
c
−
1
)
−
1
(
1
+
c
−
1
)
+
1
(
1
−
1
−
b
)
b
+
c
+
b
c
+
a
b
+
a
c
+
a
b
c
−
c
−
b
=
0
b
c
+
a
b
+
a
c
=
−
a
b
c
⇒
1
a
+
1
b
+
1
c
=
−
1
Suggest Corrections
0
Similar questions
Q.
If
1
a
+
1
b
+
1
c
=
0
, then
∣
∣ ∣
∣
1
+
a
1
1
1
1
+
b
1
1
1
1
+
c
∣
∣ ∣
∣
is equal to
Q.
If
1
a
+
1
b
+
1
c
=
0
then
∣
∣ ∣
∣
1
+
a
1
1
1
1
+
b
1
1
1
1
+
c
∣
∣ ∣
∣
=
Q.
Show that
∣
∣ ∣
∣
1
+
a
1
1
1
1
+
b
1
1
1
1
+
c
∣
∣ ∣
∣
=
a
b
c
(
1
+
1
a
+
1
b
+
1
c
)
=
a
b
c
+
b
c
+
c
a
+
a
b
.
Q.
If a, b, c all are non-zero and unequal and
∣
∣ ∣
∣
1
+
a
1
1
1
1
+
b
1
1
1
1
+
c
∣
∣ ∣
∣
=
0
, then
1
+
1
a
+
1
b
+
1
c
is equal to
Q.
a
−
1
+
b
−
1
+
c
−
1
=
0
such that
∣
∣ ∣
∣
1
+
a
1
1
1
1
+
b
1
1
1
1
+
c
∣
∣ ∣
∣
=
△
then the value of
△
is
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