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Question

If ∣∣ ∣∣1+x2312+x3123+x∣∣ ∣∣=0 then x=

A
1
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B
1
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C
6
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D
6
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Solution

The correct option is A 1
We have (1x)((2+x)(3+x)6)2(32)+3(2(2+x))=0
it gives 6x2+x3=0
x2(6+x)=0x=0,0,6
option c gives correct answer

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