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Question

If
∣ ∣ ∣(a1)2a2(a+1)2(b1)2b2(b+1)2(c1)2c2(c+1)2∣ ∣ ∣=k∣ ∣ ∣1aa21bb21cc2∣ ∣ ∣,
then the value of k is

A
4
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B
4
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C
1
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D
2
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Solution

The correct option is B 4
C3C3C1
Δ=∣ ∣ ∣(a1)2a24a(b1)2b24b(c1)2c24c∣ ∣ ∣ =4∣ ∣ ∣(a1)2a2a(b1)2b2b(c1)2c2c∣ ∣ ∣

C1C1C2+2C3
Δ=4∣ ∣ ∣1a2a1b2b1c2c∣ ∣ ∣=4∣ ∣ ∣1aa21bb21cc2∣ ∣ ∣
k=4

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