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Question

If ∣ ∣abaα+bbcbα+caα+bbα+c0∣ ∣=0, then a, b, c are in

A
AP
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B
GP
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C
HP
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D
none
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Solution

The correct option is A GP
C3C3(C1α+C2)
∣ ∣ ∣ab0bc0aα+bbα+c(aα2+2bα+c)∣ ∣ ∣=0
=5(aα2+2α+c)(acb2)=0
b2=ac
So a,b,c are in G.P
Ans: B

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