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Question

If ∣ ∣a+bb+cc+ac+aa+bb+cb+cc+aa+b∣ ∣=t×det of circulant matrix whose elements of first column are a,b,c then t equals

A
5
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B
6
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C
-2
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D
2
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Solution

The correct option is C -2
∣ ∣a+bb+cc+ac+aa+bb+cb+cc+aa+b∣ ∣=∣ ∣abccabbca∣ ∣+∣ ∣bcaabccab∣ ∣=∣ ∣abccabbca∣ ∣+∣ ∣abccabbca∣ ∣=2∣ ∣abccabbca∣ ∣=2∣ ∣abcbcacab∣ ∣
Where ∣ ∣abcbcacab∣ ∣ is the required circulant matrix

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