If ∣∣
∣∣a+bb+cc+ac+aa+bb+cb+cc+aa+b∣∣
∣∣=t×det of circulant matrix whose elements of first column are a,b,c then t equals
A
5
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B
6
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C
-2
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D
2
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Solution
The correct option is C -2 ∣∣
∣∣a+bb+cc+ac+aa+bb+cb+cc+aa+b∣∣
∣∣=∣∣
∣∣abccabbca∣∣
∣∣+∣∣
∣∣bcaabccab∣∣
∣∣=∣∣
∣∣abccabbca∣∣
∣∣+∣∣
∣∣abccabbca∣∣
∣∣=2∣∣
∣∣abccabbca∣∣
∣∣=−2∣∣
∣∣abcbcacab∣∣
∣∣ Where ∣∣
∣∣abcbcacab∣∣
∣∣ is the required circulant matrix