If a b c m n p x y z - k- then 6a 2b 2c 3m n p 3x y z - -

The correct option is D 6k #160; a amp; b amp; c m amp; n amp; p x amp; y amp; z = k, Then, #160; #160; #160 ...

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Properties of Determinants

If a b ...

Question

If $∣ ∣ ∣ ∣ \begin{matrix} a & b & c m & n & p x & y & z \end{matrix} ∣ ∣ ∣ ∣ = k$ , then $∣ ∣ ∣ ∣ \begin{matrix} 6 a & 2 b & 2 c 3 m & n & p 3 x & y & z \end{matrix} ∣ ∣ ∣ ∣ = ?$

\frac{k}{6}

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2 k

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3 k

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6 k

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Solution

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Similar questions

\sum_{k = 1}^{\infty} \frac{6^{k}}{(3^{k} - 2^{k}) (3^{k + 1} - 2^{k + 1})} =

\sum_{k = 1}^{\infty} \frac{6^{k}}{(3^{k} - 2^{k}) (3^{k + 1} - 2^{k + 1})}

(k, 2 k), (2 k, 3 k), (3, 1)

k

k^{\circ}, k^{\circ}, 2 k^{\circ}, 2 k^{\circ}, and 3 k^{\circ}

k

k - 2, 2 k + 1

6 k + 3

k

(k > 0)

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