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Question

If ∣∣ ∣∣a+xa−xa−xa−xa+xa−xa−xa−xa+x∣∣ ∣∣=0 the value of x are

A
0,a
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B
0,a
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C
a,a
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D
0,3a
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Solution

The correct option is A 0,3a
Given, ∣ ∣a+xaxaxaxa+xaxaxaxa+x∣ ∣=0
ApplyingR2R2R1 and R3R3R1

∣ ∣a+xaxax2x2x02x02x∣ ∣=0

4x2(a+x)+2x(2x(ax))2x(2x(ax))=0

4ax2+4x3+4ax24x34x3+4ax2=0

12ax24x3=0
x33ax2=0

x2(x3a)=0

x=0,x=3a

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