If sinx cos x cosx cosx sinx cosx cosx cosx sinx - 1 in the interval - -2- x -2- then tanx is

The correct option is B does not exist sinx amp; cosx amp; cosx cosx amp; sinx amp; cosx cosx amp; cosx amp; sinx =1 Put ...

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Properties of Determinants

If sinx c...

Question

If $∣ ∣ ∣ ∣ \begin{matrix} s i n x & c o s x & c o s x c o s x & s i n x & c o s x c o s x & c o s x & s i n x \end{matrix} ∣ ∣ ∣ ∣ = 1$ in the interval $\frac{- π}{2} \leq x \leq \frac{π}{2},$ then $t a n x$ is

0

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does not exist

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lim x \to 0 \frac{\sqrt{1 - cos 2 x}}{x}

| sin x | = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} sin x; & 0 < x < \frac{π}{2} - sin x; & - \frac{π}{2} < x < 0 \end{matrix}

f (x) = \frac{1 - tan x}{4 x - π}

x \neq π / 4

x \in [0, \frac{π}{2}]

f (x)

[0, \frac{π}{2}]

f (\frac{π}{4})

x

tan x = x + 1,

(π / 4, π / 2)

f (x) = 1

x < 0 = 1 + sin x

0 \leq x < π / 2,

f^{'} (x)

f (x) = \frac{sin x}{x}

(0, \frac{π}{2})

tan x > x

0 < x < \frac{π}{2}

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