If x-12 3x-1 32x-12 2 0-5x-3 4x 4-Ax-B-where A and B are constants- then the value of A-B is

Putting x = 1 A +B= 0 amp; 2 amp; 3 0 amp; 2 amp; nbsp; 0 2 amp; 4 amp; 4 ⇒ B A = 2 × ( 6) ⇒ A B nbsp; = 12 nbsp; ...

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Sarrus Rule

If x+12 3x+...

Question

If $∣ ∣ ∣ ∣ ∣ \begin{matrix} (x + 1)^{2} & 3 x + 1 & 3 2 (x + 1)^{2} & 2 & 0 - (5 x + 3) & 4 x & 4 \end{matrix} ∣ ∣ ∣ ∣ ∣ = A x + B,$
where $A$ and $B$ are constants, then the value of $A - B$ is

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∣ ∣ ∣ ∣ ∣ \begin{matrix} (x + 1)^{2} & 3 x + 1 & 3 2 (x + 1)^{2} & 2 & 0 - (5 x + 3) & 4 x & 4 \end{matrix} ∣ ∣ ∣ ∣ ∣ = A x + B,

A

B

A - B

L i m x \to \infty [\frac{x^{2} + 1}{x + 1} - a x - b] = b

\int \frac{d x}{1 + \sqrt{x + 1} + \sqrt{x}} = a x + b \sqrt{x} + c \int \sqrt{\frac{x + 1}{x}} d x

a, b, c

(a + b + c)

(- 3 x^{2} + 5 x - 2) - 2 (x^{2} - 2 x - 1)

a x^{2} + b x + c

a, b

c

b

x^{2} - 4

2 x^{3} + a x^{2} + b x + 12

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