If ∣∣
∣∣x−15x7x2−1x−182x3x0∣∣
∣∣=ax3+bx2+cx+d, then the value of c is given by
A
-1
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B
12
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C
15
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D
17
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Solution
The correct option is D 17 Differentiate w.r.t. x of given equation, we get ∣∣
∣∣150x2−1x−182x3x0∣∣
∣∣+∣∣
∣∣x−15x72x102x3x0∣∣
∣∣+∣∣
∣∣x−15x7x2−1x−18230∣∣
∣∣=3ax2+2bx+cPutx=0,wegetc=∣∣
∣∣150−1−18000∣∣
∣∣+∣∣
∣∣−107010000∣∣
∣∣+∣∣
∣∣−107−1−18230∣∣
∣∣=17