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Byju's Answer
Standard XII
Mathematics
Differentiation of a Determinant
If x+2 2x...
Question
If
∣
∣ ∣
∣
x
+
2
2
x
+
3
3
x
+
4
2
x
+
3
3
x
+
4
4
x
+
5
3
x
+
5
5
x
+
8
10
x
+
17
∣
∣ ∣
∣
=
0
then find value of
x
A
1
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B
2
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C
-1
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D
-2
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Solution
The correct options are
C
-1
D
-2
Let
Δ
=
∣
∣ ∣
∣
x
+
2
2
x
+
3
3
x
+
4
2
x
+
3
3
x
+
4
4
x
+
5
3
x
+
5
5
x
+
8
10
x
+
17
∣
∣ ∣
∣
Applying
R
2
→
R
2
−
R
1
,
R
3
→
R
3
−
R
1
Δ
=
∣
∣ ∣
∣
x
+
2
2
x
+
3
3
x
+
4
x
+
1
x
+
1
x
+
1
2
x
+
3
3
x
+
5
7
x
+
13
∣
∣ ∣
∣
=
(
x
+
1
)
∣
∣ ∣
∣
x
+
2
2
x
+
3
3
x
+
4
1
1
1
2
x
+
3
3
x
+
5
7
x
+
13
∣
∣ ∣
∣
Again applying
C
2
→
C
2
−
C
1
,
C
3
→
C
3
−
C
1
Δ
=
(
x
+
1
)
∣
∣ ∣
∣
x
+
2
x
+
1
2
x
+
2
1
0
0
2
x
+
3
x
+
2
5
x
+
10
∣
∣ ∣
∣
=
−
(
x
+
1
)
(
(
x
+
1
)
(
5
x
+
10
)
−
(
x
+
2
)
(
2
x
+
2
)
)
=
−
(
x
+
1
)
2
(
5
x
+
10
−
2
x
−
4
)
=
−
(
x
+
1
)
2
(
3
x
+
6
)
For
Δ
=
0
⇒
x
=
−
1
,
x
=
−
2
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1
Similar questions
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If
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∣ ∣
∣
x
+
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∣
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Q.
Find the value of x if
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∣ ∣
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?
Q.
If
⎛
⎜
⎝
x
−
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x
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x
−
4
x
−
4
2
x
−
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3
x
−
16
x
−
8
2
x
−
27
3
x
−
64
∣
∣ ∣
∣
=
0
,
then
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=
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