If ∣∣
∣
∣∣x2+x3x−1−x+32x+12+x2x3−3x−3x2+43x∣∣
∣
∣∣=a0+a1x+a2x2+...+a7x7, then the value of a0 is
A
25
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B
24
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C
23
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D
None of the above
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Solution
The correct option is D None of the above Given, ∣∣
∣
∣∣x2+x3x−1−x+32x+12+x2x3−3x−3x2+43x∣∣
∣
∣∣=a0+a1x+...+a7x7 On putting x=0, we get ∣∣
∣∣0−1312−3−340∣∣
∣∣=a0 ⇒0+1(0−9)+3(4+6)=a0 ⇒30−9=a0 ⇒a0=21