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Question

If ∣∣ ∣ ∣∣x2+x3x−1−x+32x+12+x2x3−3x−3x2+43x∣∣ ∣ ∣∣=a0+a1x+a2x2+...+a7x7, then the value of a0 is

A
25
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B
24
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C
23
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D
None of the above
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Solution

The correct option is D None of the above
Given, ∣ ∣ ∣x2+x3x1x+32x+12+x2x33x3x2+43x∣ ∣ ∣=a0+a1x+...+a7x7
On putting x=0, we get
∣ ∣013123340∣ ∣=a0
0+1(09)+3(4+6)=a0
309=a0
a0=21

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