CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If ∣ ∣ ∣x2+xx+1x22x2+3x13x3x3x2+2x+32x12x1∣ ∣ ∣=Ax12, then the value of A is

A
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
24
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
24
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 24
Applying R3R3R1R2R22R1

∣ ∣x2+xx+1x2x1x2x+1x+3x2x+1∣ ∣

Applying R3R3R2

∣ ∣x2+xx+1x2x1x2x+1400∣ ∣

=4[(x+1)2(x2)2]

=4[2x+4x+14]

=24x12

Ax12=24x12

A=24

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon