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Question

If ∣ ∣ ∣x2+xx+1x22x2+3x13x3x3x2+2x+32x12x1∣ ∣ ∣=ax12, then value of a2 is

A
576
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B
24
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C
216
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D
215
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Solution

The correct option is A 576
∣ ∣ ∣x2+xx+1x22x2+3x13x3x3x2+2x+32x12x1∣ ∣ ∣=ax12
at x=1
∣ ∣221430611∣ ∣=a12
a12=2(30)2(4)1(418)
=68+14=12
a=12+12=24
a2=516

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