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Question

If ∣ ∣ ∣x2+xx+1x22x2+3x13x3x3x2+2x+32x12x1∣ ∣ ∣=ax12, then a is equal to

A
29
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B
24
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C
32
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D
21
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Solution

The correct option is B 24
Given, ∣ ∣ ∣x2+xx+1x22x2+3x13x3x3x2+2x+32x12x1∣ ∣ ∣=ax12
R1R1+R3
∣ ∣ ∣2x2+3x+33x3x32x2+3x13x3x3x2+2x+32x12x1∣ ∣ ∣=ax12
R1R1R2
∣ ∣ ∣4002x2+3x13x3x3x2+2x+32x12x1∣ ∣ ∣=ax12
4[6x23x6x2+6x+3x3]=ax12
24x12=ax12
On comparing, we get
a=24

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