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Question

Ifz2z=1 then Range of|Z| is


A

[0, 1]

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B

[1, 2]

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C

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D

[0, 2]

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Solution

The correct option is B

[1, 2]


||Z1||Z2|||Z1±Z2|r2r1,|z|=r1r2r11r2


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