Question

If body having initial velocity zero is moving with uniform acceleration of $8{\text{m/sec}}^2$, the distance travelled by it in fifth second will be

• A. $36\text{m}$
• B. $40\text{m}$
• C. $30\text{m}$
• D. $\text{Zero}$

Answer 1

The correct option is A $36\text{m}$

Given, $u=0,a=8{\text{m/sec}}^2,n=5$
As we know that the distance travelled in $n^{\text{th}}$ second is given by
$S_n=u+\frac{a}{2}(2n-1)$
So, distance travelled in $5^{\text{th}}$ second is
$S_{5^{th}}=0+\frac{8}{2}(2\times 5-1)=36\text{m}$