If both gases have same temperature so rate of diffusion of $O_{2}$ will be:

four times of

H e

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two times of

H e

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0.35 times of

H e

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eight times of

H e

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Solution

The correct option is B 0.35 times of $H e$
$\frac{r a t e_{H e}}{r a t e_{O_{2}}} = \sqrt{\frac{M_{O_{2}}}{M_{H e}}} = \sqrt{\frac{32}{4}} = \sqrt{8} = 2.828$
$\Rightarrow r a t e_{O_{2}} = r a t e_{H e} \times 0.35$ .

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If both gases have same temperature so rate of diffusion of O2 will be:

The correct option is B 0.35 times of HerateHerateO2=√MO2MHe=√324=√8=2.828⇒rateO2=rateHe×0.35 .

If both gases have same temperature so rate of diffusion of $O_{2}$ will be:

The correct option is B 0.35 times of $H e$
$\frac{r a t e_{H e}}{r a t e_{O_{2}}} = \sqrt{\frac{M_{O_{2}}}{M_{H e}}} = \sqrt{\frac{32}{4}} = \sqrt{8} = 2.828$
$\Rightarrow r a t e_{O_{2}} = r a t e_{H e} \times 0.35$ .