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Question

If both the roots of ax2+bx+c=0 are real, positive and distinct, then
(where Δ=b24ax)

A
Δ>0,ab<0,ac>0
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B
Δ>0,ab<0,ac<0
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C
Δ>0,ab>0,bc>0
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D
Δ>0,ab<0,bc>0
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Solution

The correct option is A Δ>0,ab<0,ac>0
Roots are real, positive and distinct
Δ>0 and graph of f(x)=ax2+bx+c will cut the xaxis in positive direction.

Case 1: a<0
Here, c<0 because curve intersects with y axis in ve region
b2a>0b>0 (x coordinate of vertex is+ve
ab<0,ac>0

Case 2:a>0
Here, c>0 because curve intersects with y axis in +ve region.
b2a>0b<0 (x coordinate of vertex is+ve
ab<0,ac>0

Alternate solution:
For real, positive and distinct roots.
Δ>0, sum of roots >0, product of root >0
Δ>0,ba>0, ca>0Δ>0, aba2>0, aca2>0Δ>0, ab<0, ac>0

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