If both the roots of ax2+bx+c=0 are real, positive and distinct, then (where Δ=b2−4ax)
A
Δ>0,ab<0,ac>0
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B
Δ>0,ab<0,ac<0
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C
Δ>0,ab>0,bc>0
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D
Δ>0,ab<0,bc>0
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Solution
The correct option is AΔ>0,ab<0,ac>0 ∵ Roots are real, positive and distinct ∴Δ>0 and graph of f(x)=ax2+bx+c will cut the x−axis in positive direction.
Case 1:a<0 Here, c<0 because curve intersects with y− axis in −ve region −b2a>0⇒b>0(∵x coordinate of vertex is+ve ⇒ab<0,ac>0
Case 2:a>0 Here, c>0 because curve intersects with y− axis in +ve region. −b2a>0⇒b<0(∵x coordinate of vertex is+ve ⇒ab<0,ac>0
Alternate solution: For real, positive and distinct roots. Δ>0, sum of roots >0, product of root >0 ⇒Δ>0,−ba>0,ca>0⇒Δ>0,−aba2>0,aca2>0⇒Δ>0,ab<0,ac>0