Question

If both the roots of the equation $x^2-9x+a=0$ are positive and one is greater than $3$ and other is less than $3$, then all possible values of $a$ is-

• A. $0<a<18$
• B. $-18<a<0$
• C. $-1<a<2$
• D. none of these

Answer 1

Answer: (A)

$0<a<18$

$\therefore f\left(0\right)>00-0+a>0a>0andf\left(3\right)<03^2-9.3+a<0a-18<0\therefore a\in (0,18)$