If both x−2 and x−12 are factors of px2+5x+r , then .
A
p=r
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B
p+r=0
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C
p+2r=0
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Solution
The correct option is Ap=r px2+5x+r=0−−−(1) (x−2)(x−12)=0
[since it is factors] x2−x2−2x+1=0 x2−(x+4x2)+1=0 2x2−5x+2=0−−−(2)
Comparing equation(1) and equation(2), we get p=r