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Question

If both x2 and x12 are factors of px2+5x+r , then .

A
p=r
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B
p+r=0
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C
p+2r=0
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Solution

The correct option is A p=r
px2+5x+r=0(1)
(x2)(x12)=0
[since it is factors]
x2x22x+1=0
x2(x+4x2)+1=0
2x25x+2=0(2)
Comparing equation(1) and equation(2), we get
p=r

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