Question

If BP:PC = 1:2 and area $\Delta$CPQ = 20 sq.cm, then which of the shaded regions has an area of 10sq.cm.

• A.
• B.
• C.

Answer 1

The correct option is A

$\frac{area\left(\Delta BQP\right)}{area\left(\Delta CPQ\right)}=\left(\frac{1}{2}\right)$
Since triangles having common vertex and bases along the same straight line .
$\frac{area\left(\Delta BQP\right)}{20}=\frac{1}{2}$
$area\left(\Delta BQP\right)$ = 10sq.cm