Question

If bullet of mass $5$ $gm$ moving with velocity $100$ $m/sec$, penetrates the wooden block upto $6$ $cm$. Then the average force imposed by the bullet on the block is

• A. $8300$ $N$
• B. $417$ $N$
• C. $830$ $N$
• D. $Zero$

Answer 1

The correct option is C $830$ $N$

$F=ma$

$a=\frac{v}{t}$ and $t=\frac{x}{v}$

Mass in $kg$,

$a=\frac{v^2}{x}=\frac{{100}^2}{6\times {10}^{-2}}$

$F=\frac{5}{1000}\times \frac{{100}^2}{6\times {10}^{-2}}=833.33$ $N$