If by dividing a three-digit number 3BA by 10, we get quotient as 34, then find the values of A and B.
B = 4
A = 0
3BA10=34
Since there is no remainder, 3BA is completely divisible by 10.
If a number is divisible by 10, then the number will have 0 in its ones place.
⇒A=0
So,
3B010=34
⇒3B0=340
⇒B=4