If by Neil's Bohr formula the no. Of electrons is 2n^2 . And if 3rd shell contains 18 electrons . Why did he said that the outermost shell can maximum hold 8 shells?

Open in App

Solution

when n=2 no of electrons is 8.An atom with atomic number 10 has electronic configuration 2,8.
Ie,upto 10(greater than 2) atoms can hold maximum of 8 electron in outermost shell.But n>2 it's capacity increases and can hold more than 8 electron.
You may read this for an atom whose atomic number less than 10.It's true for such elements.But atomic number increases,it can hold more than 8.

Suggest Corrections

Similar questions

The maximum no. of electrons in a shell can be given by the formula

2 n^{2}

Calculate the maximum no. of electrons in the 'N shell'.

Can u pls explain this rule 2 :The outermost shell cannot have more than 8 electrons. The penultimate shell cannot have more than 18 electrons. A new shell is formed as soon as the outermost shell attains 8 electrons

Q. If the maximum shell of electron (N shell) can contain 32 electrons, then why it can contain a maximum of only 8 valence electrons? Please explain me this in detail.

We were told that maximum number of electrons in the last shell is given by the formula 2n²_{^{. But we were also told it at the maximum number of electrons the last I can accommodate is 8.But acoording to the formula 3rd shell can accomodate 18 electrons. Please explain}}

Join BYJU'S Learning Program