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Question

If c>0 and the equation 3ax2+4bx+c=0 has no real root, then

A
2a+c>b
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B
a+2c>b
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C
3a+c>4b
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D
a+3c<b
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Solution

The correct option is C 3a+c>4b
f(0)>0
f(1)>0So, 3a4b+c>03a+c>4b

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