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Question

If C0,C1,C2,.....Cn denote the coefficient in the expansion of (1+x)n, then the value of C1+2C2+3C3....+nCn is

A
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Solution

The correct option is A
In (1+x)n=C0+C1x+C2x2+......+CnxnDifferentiate both sides w.r.t. xn(1+x)n1=C1+2C2x+....+nCnxn1,put x=1n.2n1=C1+2C2x+....+nCn

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