Question

If $C_1$ and $C_2$ are incircle and excircle respectively of $a△$ whose sides are $3cm,4cm,5cm$, then find the $\frac{\arg of{C}_1}{\arg of{C}_2}$

Answer 1

not arg but it is area

$s=\frac{a+b+c}{2}=\frac{3+4+5}{2}=6$

$\frac{areaofC1}{areaofC2}=\frac{\pi r^2}{\pi r_1^2}=(\frac{r}{r_1}{)}^2=(\frac{s-a}{s}{)}^2=(1-\frac{a}{s}{)}^2=(1-\frac{1}{2}{)}^2=\frac{1}{4}$