Question

If $C_4{H}_{9}Cl$ with $Na/ether$ gives $2,5$-dimethylhexane, then the compound, $C_4{H}_{9}Cl$ is:

• A. n-butylchloride
• B. sec-butylchloride
• C. iso-butylchloride
• D. tert-butylchloride

Answer 1

The correct option is C iso-butylchloride

The reaction of Isobutyl chloride $\left(C_4{H}_{9}Cl\right)$ with $Na/Ether$ gives $2,5$-dimethylhexane. This is a condensation reaction in which two molecules of sodium chloride are obtained for every molecule of $2,5$-dimethylhexane.

Option C is correct.