If c be a given non-zero scalar, and A and B be given non-zero vectors such that A⊥B, find the vector X which satisfies the equations A. X=c and A×X=B
A
X=cA+A×B|A|2
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B
X=cA−A×B|A|2
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C
X=cB−A×B|B|2
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D
X=cB+A×B|B|2
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Solution
The correct option is BX=cA−A×B|A|2 We are given A.X=c...(1) A×X=B ...(2) Taking cross-product with A on both sides of (2), A×(A×X)=A×B i.e., (A.X)A−(A.A)X=A×B. Now using (1), we get cA−|A|2X=A×B or X|A|2=cA−A×B∴X=cA−A×B|A|2.